NEW FUNCTION

Function Expression :

\[f(x)=\frac{8(x-2 )(x^2-2x+4 )e^{x-4}}{x^3} \]

Domain

\[\left]-\infty, 0\right[ \cup \left]0, \infty\right[ \]

Limits

\[\lim_{x \rightarrow-\infty}f(x) = 0 \]
\[\lim_{x \overset{<}{\rightarrow0} }f(x) = +\infty \]
\[\lim_{x \overset{>}{\rightarrow0} }f(x) = -\infty \]
\[\lim_{x \rightarrow+\infty}f(x) = +\infty \]
\[ \]

Derivate

\[f^{\,\prime}(x)=\frac{\left(2 x - 2\right) \left(8 x - 16\right) e^{x - 4} + \left(8 x - 16\right) \left(x^{2} - 2 x + 4\right) e^{x - 4} + \left(8 x^{2} - 16 x + 32\right) e^{x - 4}}{x^{3}} - \frac{24 \left(x - 2\right) \left(x^{2} - 2 x + 4\right) e^{x - 4}}{x^{4}} \]
\[f^{\,\prime}(x)=\frac{8 \left(x^{4} - 4 x^{3} + 12 x^{2} - 24 x + 24\right) e^{x - 4}}{x^{4}} \]
\[ \]

Integral

\[F(x) = \frac{\left(8 x^{2} - 32 x + 32\right) e^{x - 4}}{x^{2}} \]

Sign Table


Variation Table


Plot


Elapsed Time: 0.0268 seconds