NEW FUNCTION
Function Expression :
\[f(x)=\frac{x^2-8x+4}{x-1} \]
Domain
\[\left]-\infty, 1\right[ \cup \left]1, \infty\right[ \]
Limits
\[\lim_{x \rightarrow-\infty}f(x) = -\infty \]
\[\lim_{x \overset{<}{\rightarrow1} }f(x) = +\infty \]
\[\lim_{x \overset{>}{\rightarrow1} }f(x) = -\infty \]
\[\lim_{x \rightarrow+\infty}f(x) = +\infty \]
\[ \]
Derivate
\[f^{\,\prime}(x)=\frac{2 x - 8}{x - 1} - \frac{x^{2} - 8 x + 4}{\left(x - 1\right)^{2}} \]
\[f^{\,\prime}(x)=\frac{x^{2} - 2 x + 4}{x^{2} - 2 x + 1} \]
\[ \]
Integral
\[F(x) = \frac{x^{2}}{2} - 7 x - 3 \log{\left(x - 1 \right)} \]
Sign Table
Variation Table
Plot
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